document.write( "Question 99076: I am thinking of three consecutive positive numbers. If i multiply the first with the third and then add the second, the result is 41. Let x be the smallest number. \n" ); document.write( "
Algebra.Com's Answer #72091 by rmromero(383)\"\" \"About 
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document.write( "I am thinking of three consecutive positive numbers.  If i multiply the first with the third and then add the second, the result is 41.  Let x be the smallest number.\r
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document.write( "What is asked in the problem?
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document.write( "  find the 3 consecutive positive numbers.\r
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document.write( "Given:
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document.write( "  the first is multiplied with the third and then add the second, the result is 41.\r
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document.write( "Representation:
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document.write( "  Let x be the smallest number
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document.write( "     x + 1 be the second number
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document.write( "    x + 2 be the third/greatest number\r
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document.write( "Equation:\r
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document.write( "          x (x+2) + x+1 = 41
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document.write( "       x^2 + 2x + x + 1 = 41
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document.write( "           x^2 + 3x + 1 = 41
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document.write( "          x^2 + 3x - 40 = 0
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document.write( "        (x + 8) (x - 5) = 0\r
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document.write( "   x + 8 = 0    and    x - 5 = 0
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document.write( "     x = -8            x = 5\r
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document.write( "Since we are asked to find the three consecutive POSITIVE number
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document.write( "we reject -8.\r
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document.write( "x = 5
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document.write( "x + 1 = 5 + 1 = 6
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document.write( "x + 2 = 5 + 2 = 7\r
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document.write( "Therefore the three consecutive POSITIVE integers are 5, 6, and 7.\r
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