document.write( "Question 1105985: Suppose that you are in a class of 31 students and it is assumed that approximately 16% of the population is left-handed.
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document.write( "(a) Compute the probability that exactly five students are left-handed.
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document.write( "(b) Compute the probability that at most four students are left-handed.
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document.write( "(c) Compute the probability that at least six students are left-handed. \n" );
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Algebra.Com's Answer #720905 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! a. This is 31C*50.16^5*0.84^26=0.1915 \n" ); document.write( "b. At most 4 is \n" ); document.write( "31C4*0.16^4*0.84^27=0.1861 \n" ); document.write( "31C3*0.16^3*0.84^28=0.1396 \n" ); document.write( "31C2*0.16^2*0.84^29=0.0758 \n" ); document.write( "next is 0.0265 \n" ); document.write( "0 is 0.84^31=0.0045 \n" ); document.write( "They add up to 0.4325 ANSWER \n" ); document.write( "Count the first one for at least 6 students, and the probability of 5 and under is 0.627, so the complement is at least 6, and that is 0.373 ANSWER \n" ); document.write( " |