document.write( "Question 1105957: The width of the rectangle is 4/5 of its dimension. Find the dimension of the rectangle if the perimeter become 62cm when each dimension is increased by 2cm. \n" ); document.write( "
Algebra.Com's Answer #720902 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "If each dimension was increased by 2cm, then the perimeter was increased by 8cm. So the original perimeter was 62-8=54cm.

\n" ); document.write( "The width is 4/5 the length, so call the width 4x and the length 5x.

\n" ); document.write( "Width plus length is half the perimeter:
\n" ); document.write( "\"4x%2B5x=54%2F2+=+27\"
\n" ); document.write( "\"9x=27\"
\n" ); document.write( "\"x=3\"

\n" ); document.write( "The length is 4x=12cm; the length is 5x=15cm.
\n" ); document.write( "
\n" );