document.write( "Question 1105949: A particle is moving according to an equation of motion. Its position after t seconds is given by s(t) = 2t^3 - 11t^2 + 13t - 1. After 1 second its position is at 3. Where is the original position of the particle? Explain.
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Algebra.Com's Answer #720861 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "A particle is moving according to an equation of motion. Its position after t seconds is given by s(t) = 2t^3 - 11t^2 + 13t - 1.
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document.write( "0.  The info  \"After 1 second its position is at 3.\" is EXCESSIVE, UNNECESSARY and is not used in the solution.\r\n" );
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document.write( "    It is overlayed by this statement: \r\n" );
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document.write( "        \"A particle is moving according to an equation of motion. \r\n" );
document.write( "         Its position after t seconds is given by s(t) = 2t^3 - 11t^2 + 13t - 1.\"\r\n" );
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document.write( "1.  \"Where is the original position of the particle?\"\r\n" );
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document.write( "    Answer:  Substitute t= 0 into the formula and calculate s(0).\r\n" );
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document.write( "2.  \"How far from the starting point is the particle at the end of 5 seconds?\".\r\n" );
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document.write( "    Answer:  Substitute t= 5 into the formula and calculate s(5).\r\n" );
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document.write( "             Then calculate  delta_s = s(5) - s(0).\r\n" );
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document.write( "             It will be your final answer.\r\n" );
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