document.write( "Question 99068: Could you please explain how to do this.\r
\n" ); document.write( "\n" ); document.write( "graph this equation
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Algebra.Com's Answer #72084 by edjones(8007)\"\" \"About 
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2/3x+y/3=-1/3
\n" ); document.write( "subtract 2/3x from each side: y/3=-2/3x-1/3
\n" ); document.write( "multiply 3 times each side: y=-2x-1 this is called the slope-intercept form.
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=-2%2Ax-1\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-5
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\n" ); document.write( " \"y=-2%2A%28-5%29-1\"
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\n" ); document.write( " \"y=10-1\" Multiply
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\n" ); document.write( " \"y=9\" Add
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\n" ); document.write( " So here's one point (-5,9)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-4
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\n" ); document.write( " \"y=-2%2A%28-4%29-1\"
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\n" ); document.write( " \"y=8-1\" Multiply
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\n" ); document.write( " \"y=7\" Add
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\n" ); document.write( " So here's another point (-4,7). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=-2%2Ax-1\" through the points (-5,9) and (-4,7)
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\n" ); document.write( " So from the graph we can see that the slope is \"-2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 1 units to get to the next point), the y-intercept is (0,\"-1\")and the x-intercept is (\"-0.5\",0) ,or (\"-1%2F2\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=-1\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"-1\").
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\n" ); document.write( " So we have one point (0,\"-1\")
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\n" ); document.write( " Now since the slope is \"-2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"-1\"), we can go down 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=-2%2Ax-1\"
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\n" ); document.write( " So this is the graph of \"y=-2%2Ax-1\" through the points (0,-1) and (1,-3)
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