document.write( "Question 1105910: A woman had two investments, one paying a 6% dividend. The other is $680 more than half the first investment and pays a 5% dividend. If the total return is $102, find the investments.
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\n" ); document.write( "A man invested a total of $1200 into two accounts, one paying a 4% dividend, the other paying a 6% dividend. The total interest earned was $57. How much was invested into each account?
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Algebra.Com's Answer #720832 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "A man invested a total of $1200 into two accounts, one paying a 4% dividend, the other paying a 6% dividend.
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document.write( "    x +     y = 1200,    (1)   (\"A man invested a total of $1200 into two accounts\")\r\n" );
document.write( "0.04x + 0.06y =   57.    (2)   (\"The total interest earned was $57\")\r\n" );
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document.write( "Thus you have the system of 2 equations in 2 unknowns.\r\n" );
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document.write( "You can solve it using the substitution method.\r\n" );
document.write( "For it, express y = 1200-x from the first equation and substitute it into the second equation. You will get\r\n" );
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document.write( "0.04x + 0.06*(1200-x) = 57,\r\n" );
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document.write( "0.04x + 72 - 0.06x = 57  ====>  -0.02x = 57 - 72 = -15  ====>  x =  = 750.\r\n" );
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document.write( "So, $750 was invested at 4% and the rest  $1200 - $750 = $450 was invested at 6%.\r\n" );
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document.write( "Check.  0.04*750 + 0.06*450 = 57 dollars.   ! Correct !\r\n" );
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document.write( "Answer.  $750 was invested at 4% and $450 was invested at 6%.\r\n" );
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\n" ); document.write( "To see other similar solved problems on investment, look into the lesson\r
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\n" ); document.write( "Never put more than one problem into your post.\r
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\n" ); document.write( "\n" ); document.write( "It is the RULE of this forum.\r
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\n" ); document.write( "\n" ); document.write( "By doing so, you work AGAINST your better interests.\r
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