document.write( "Question 99026: A plane flies 720 mi against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10h, what is the plane's speed in still air? \n" ); document.write( "
Algebra.Com's Answer #72083 by checkley71(8403)\"\" \"About 
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10=720/(X-30)+720/(X+30)
\n" ); document.write( "10=[720(X+30)+720(X-30)/(X-30)(X+30)]
\n" ); document.write( "10=[720X+2160+720X-2160]/(X^2-900) NOW CROSS MULTIPLY
\n" ); document.write( "10X^2-9000=1440X
\n" ); document.write( "10X^2-1440X-9000=0
\n" ); document.write( "10(X^2-144-900)=0
\n" ); document.write( "10(X-150)(X+6)=0
\n" ); document.write( "X-150=0
\n" ); document.write( "X=150 FOR THE SPEED OF THE AIRPLANE IN STILL AIR.
\n" ); document.write( "PROOF
\n" ); document.write( "10=(720/120+720/180)
\n" ); document.write( "10=6+4
\n" ); document.write( "10=10\r
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