document.write( "Question 99026: A plane flies 720 mi against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10h, what is the plane's speed in still air? \n" ); document.write( "
Algebra.Com's Answer #72083 by checkley71(8403) ![]() You can put this solution on YOUR website! 10=720/(X-30)+720/(X+30) \n" ); document.write( "10=[720(X+30)+720(X-30)/(X-30)(X+30)] \n" ); document.write( "10=[720X+2160+720X-2160]/(X^2-900) NOW CROSS MULTIPLY \n" ); document.write( "10X^2-9000=1440X \n" ); document.write( "10X^2-1440X-9000=0 \n" ); document.write( "10(X^2-144-900)=0 \n" ); document.write( "10(X-150)(X+6)=0 \n" ); document.write( "X-150=0 \n" ); document.write( "X=150 FOR THE SPEED OF THE AIRPLANE IN STILL AIR. \n" ); document.write( "PROOF \n" ); document.write( "10=(720/120+720/180) \n" ); document.write( "10=6+4 \n" ); document.write( "10=10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |