document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105636>Question 1105636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if A,B and C  are mutually exclusive events and p(A) =0.2,p(B)=0.3 p(C)=0.2find (a) p(A union B union C),(b) p(Acomplement intersect (B union C)), (c) p(B union C complement ) complement\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720800 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(a) The events are mutually exclusive, so P(A union B union C) is just P(A)+P(B)+P(C) = 0.2+0.3+0.2 = 0.7<br><BR>\n" );
document.write( "(b) Again since the events are mutually exclusive, (A complement) intersect (B union C) is just B union C; so P[(A complement) intersect (B union C)] is P(B union C) = P(B)+P(C) = 0.3+0.2 = 0.5<br><BR>\n" );
document.write( "(c) Once more, since the events are mutually exclusive, B union C complement is just C complement; the complement of that set is C.  So P((B union C complement)complement) = P(C) = 0.2 </SPAN>\n" );
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