document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105891>Question 1105891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4.	Claire is considering investing in a new business. In the first year, there is a probability of 0.2 that the new business will lose $10,000, a probability of 0.4 that the new business will break even ($0 loss or gain), a probability of 0.3 that the new business will make $5,000 in profits, and a probability of 0.1 that the new business will make $8,000 in profits. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720788 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not clear what asked for but maybe Expected Value E(x)=sum x*p(x)<BR>\n" );
document.write( "This is <BR>\n" );
document.write( "MINUS 0.2*10000=-$2000<BR>\n" );
document.write( "0.4*0=0<BR>\n" );
document.write( "0.3*5000=$1500<BR>\n" );
document.write( "0.1*8000=$800<BR>\n" );
document.write( "E(x)=$2300-$2000=+$300.<BR>\n" );
document.write( "This would make it reasonable to invest. </SPAN>\n" );
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