document.write( "Question 99055This question is from textbook Algebra 2
\n" ); document.write( ": Write an equation in slope-intercept form for each given pair.\r
\n" ); document.write( "\n" ); document.write( " Can you please help me write an equation in slope-intercept form?\r
\n" ); document.write( "\n" ); document.write( "20. (2.5, 2)\r
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\n" ); document.write( "\n" ); document.write( "22. (4, 3), (7, -2)\r
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\n" ); document.write( "\n" ); document.write( "Thankyou a bunch!!!!!!
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Algebra.Com's Answer #72077 by checkley71(8403)\"\" \"About 
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20) (2.5,2) SORRY A SLOPE INTERCEPT EQUATION CANNOT BE FORMED USING ONE X,Y CORDINATE.
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\n" ); document.write( "22) (4,3)(7,-2) HERE WE CAN DEFINE THE SLOPE (Y2-Y1)/(X2-X1)
\n" ); document.write( "(-2-3)/(7-4)=-5/3 IS THE SLOPE (m)
\n" ); document.write( "NOW USING ONE SET OF X,Y POINTS & THIS SLOPE OF -5/3 WE USE THE LINE FORMULA [Y=mX+b] TO FING THE Y INTERCEPT (b).
\n" ); document.write( "3=4*-5/3+b
\n" ); document.write( "3=-20/3+b
\n" ); document.write( "b=3+20/3
\n" ); document.write( "b=(9+20)/3
\n" ); document.write( "b=29/3 SO THE LINE EQUATION WITH A SLOPE OF -5/3 THROUGH THESE TWO POINTS IS:
\n" ); document.write( "Y=-5X/3+29/3
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+8%2C+-10%2C+10%2C+y+=+-5x%2F3+%2B29%2F3%29+\" (graph 300x200 pixels, x from -6 to 8, y from -10 to 10, y = -5x/3 +29/3).
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