document.write( "Question 1105846: In triangle ABC ,PQ is parallel to AC and PQ divides triangular region ABC into two parts such that ar(BPQ)=1/4 at(PQCA). Find BP:PA.
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Algebra.Com's Answer #720749 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If the area of triangle BPQ is 1/4 the area of trapezoid PQCA, then the area of triangle BPQ is 1/5 the area of triangle ABC. \n" ); document.write( "Since triangles ABC and PBQ are similar, the ratio of their areas is the square of the scale factor between the two triangles. \n" ); document.write( "Since the ratio of areas is 1:5, the scale factor is 1:sqrt(5); that makes BP:AB = 1:sqrt(5). And that makes BP:PA = 1:(sqrt(5)-1). \n" ); document.write( " |