document.write( "Question 99024: Hello,\r
\n" ); document.write( "\n" ); document.write( " Please help me with this story problem. I got 20 mi...but want to check.\r
\n" ); document.write( "\n" ); document.write( "Two cars leave an intersection. One car travels north; the other east. When the car traveling north had gone 15 mi, the distance between the cars was 5 mi more than the distance traveled by the car heading east. How far had the east bound car travled? Thanks..>Tammy
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Algebra.Com's Answer #72066 by doukungfoo(195)\"\" \"About 
You can put this solution on YOUR website!
Yes 20 miles is the correct answer. You should have used the Pythagorean theorem \"a%5E2%2Bb%5E2=c%5E2\"to solve this problem. The variable a is used to represent the distance traveled by the north bound car, so the a=15. The b variable is the unknown distance traveled by the east bound car, so b=x. Finally the c variable is the distance between the two cars which is given to be 5 more miles than the distance traveled by the east bound car, so c= x+5.
\n" ); document.write( "Now we can plug in these values to the Pythagorean formula and solve for x. Here is how it works out.\r
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\n" ); document.write( "\n" ); document.write( "\"15%5E2%2Bx%5E2=%28x%2B5%29%5E2\"
\n" ); document.write( "\"225%2Bx%5E2=%28x%2B5%29%28x%2B5%29\"
\n" ); document.write( "\"225%2Bx%5E2=x%5E2%2B5x%2B5x%2B25\"
\n" ); document.write( "\"225%2Bx%5E2=x%5E2%2B10x%2B25\"
\n" ); document.write( "\"200=10x\"
\n" ); document.write( "\"20=x\"
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