document.write( "Question 1105697: Hi
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document.write( "a b c were waiting to start a race.c was 150m ahead of b and a was 50m behind b. At 8am they started the race.a overtook b in 2 min.in another 3 min a overtook c. If b speed was 120m/min at what time did b overtake c, assume they all ran at a constant speed throughout the race.\r
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document.write( "thanks
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Algebra.Com's Answer #720598 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a b c were waiting to start a race. \n" ); document.write( "c was 150m ahead of b and \n" ); document.write( "a was 50m behind b. \n" ); document.write( "At 8am they started the race. \n" ); document.write( "a overtook b in 2 min.in another 3 min a overtook c. \n" ); document.write( " If b speed was 120m/min at what time did b overtake c? \n" ); document.write( ": \n" ); document.write( "Find a's speed \n" ); document.write( "In 2 min b traveled 240m \n" ); document.write( "a traveled 240 + 50 = 290m in 2 min, therefore \n" ); document.write( "290/2 = 145 m/min is a's speed \n" ); document.write( ": \n" ); document.write( "Find c's speed \n" ); document.write( "At start c was 200m ahead of a \n" ); document.write( "It took a, 5 min to overtake c \n" ); document.write( "in 5 min a travels 5(145) = 725m \n" ); document.write( "c traveled 725 - 200 = 525m, therefore \n" ); document.write( "525/5 = 105 m/sec is c's speed \n" ); document.write( ": \n" ); document.write( "\"If b speed was 120m/min at what time did b overtake c?\" \n" ); document.write( "b was 150m behind c \n" ); document.write( "let t = time for b to catch c, write a dist equation (dist = speed * time) \n" ); document.write( "120t = 105t + 150 \n" ); document.write( "120t - 105t = 150 \n" ); document.write( "15t = 150 \n" ); document.write( "t = 150/15 \n" ); document.write( "t = 10 min \n" ); document.write( "b catches c at 8:10\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |