document.write( "Question 99017: A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the brand that is 25% grape juice was used? What are the steps to determine the answer? \n" ); document.write( "
Algebra.Com's Answer #72059 by stanbon(75887)\"\" \"About 
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A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the brand that is 25% grape juice was used? What are the steps to determine the answer?
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\n" ); document.write( "Comment: grape drink is made up of grape juice and water. You need to
\n" ); document.write( "keep track of the grape juice or the water in each of the solutions.
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\n" ); document.write( "25% grape juice DATA:
\n" ); document.write( "Amount = x gallons ; Amt of grape in it is 0.25x gallons
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\n" ); document.write( "75% grape juice DATA:
\n" ); document.write( "Amount = \"7-x\" gallons; Amt of grape in it is 0.75(7-x) = 5.25-0.75x gallons
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\n" ); document.write( "35% mixture DATA:
\n" ); document.write( "Amount = 7 gallons: amt of grape is 0.35*7 = 2.45 gallons
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\n" ); document.write( "EQUATION:
\n" ); document.write( "grape + grape = grape
\n" ); document.write( "0.25x + 5.25-0.75x = 2.45
\n" ); document.write( "-0.50x = -2.8
\n" ); document.write( "x = 5.6 gallons (amount of 25% grape juice that must be added)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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