document.write( "Question 99017: A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the brand that is 25% grape juice was used? What are the steps to determine the answer? \n" ); document.write( "
Algebra.Com's Answer #72059 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A brand of grape drink that is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of grape drink that is 35% grape juice. How much of the brand that is 25% grape juice was used? What are the steps to determine the answer? \n" ); document.write( "-------------- \n" ); document.write( "Comment: grape drink is made up of grape juice and water. You need to \n" ); document.write( "keep track of the grape juice or the water in each of the solutions. \n" ); document.write( "-------------------- \n" ); document.write( "25% grape juice DATA: \n" ); document.write( "Amount = x gallons ; Amt of grape in it is 0.25x gallons \n" ); document.write( "----------------- \n" ); document.write( "75% grape juice DATA: \n" ); document.write( "Amount = \"7-x\" gallons; Amt of grape in it is 0.75(7-x) = 5.25-0.75x gallons \n" ); document.write( "------------------- \n" ); document.write( "35% mixture DATA: \n" ); document.write( "Amount = 7 gallons: amt of grape is 0.35*7 = 2.45 gallons \n" ); document.write( "------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "grape + grape = grape \n" ); document.write( "0.25x + 5.25-0.75x = 2.45 \n" ); document.write( "-0.50x = -2.8 \n" ); document.write( "x = 5.6 gallons (amount of 25% grape juice that must be added) \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |