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You can put this solution on YOUR website!
plane leaves the airport and travels S 46 degrees E at 440 mph.
\n" ); document.write( " Another plane leaves the same airport half an hour later and travels N 28 degrees E at 475 mph.
\n" ); document.write( " How far apart are the planes 1.5 hours after the second plane leave the airport.
\n" ); document.write( ":
\n" ); document.write( "find the angle between the paths of the two planes.
\n" ); document.write( " Convert to true bearing, (ref to 0 degrees)
\n" ); document.write( "S 46E: 180 - 46 = 134 degree
\n" ); document.write( "N 28E: 28 degrees
\n" ); document.write( "134 - 28 = 106 degrees is angle between the paths of the two planes
\n" ); document.write( ":
\n" ); document.write( "1.5 + .5 = 2 hrs is the flying time of the 1st plane
\n" ); document.write( "then
\n" ); document.write( "2(440) = 880 mi flown by the 1st plane
\n" ); document.write( "and
\n" ); document.write( "1.5(475) = 712.5 mi flown by the 2nd plane
\n" ); document.write( ":
\n" ); document.write( "Use the law of cosines: a^2 = b^2 + c^2 - 2(b*c)*cos(A), where
\n" ); document.write( "A = 106 degrees
\n" ); document.write( "a = distance between the two planes
\n" ); document.write( "b = 880
\n" ); document.write( "c = 712.5
\n" ); document.write( ":
\n" ); document.write( "a^2 = 880^2 + 712^2 - 2(880*712.5)*cos(106)
\n" ); document.write( "I'll let you do the tedious math here, I got
\n" ); document.write( "a = 1275.8 mi apart \n" ); document.write( "