document.write( "Question 1105661: ABCD is a rectangle. BC = 15m and DC = 8 m. BD is the diagonal. F is a point on BD. F is joint to C, such that FC is perpendicular BD. Similarly, E another point on BD and AE jointed such that AE is perpendicular to BD. What is the distance from point E to F. in m. \n" ); document.write( "
Algebra.Com's Answer #720523 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "By applying the Pythagorean theorem to right ΔBCD,\r\n" );
document.write( "BD = 17\r\n" );
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document.write( "ΔBCD ∽ ΔCFD because they are right triangles with a common\r\n" );
document.write( "acute angle, so\r\n" );
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document.write( "\"FD%2FDC\"\"%22%22=%22%22\"\"+DC%2FBD\"\r\n" );
document.write( "\"FD%2F8\"\"%22%22=%22%22\"\"+8%2F17\"\r\n" );
document.write( "\"17%2AFD\"\"%22%22=%22%22\"\"+8%2A8\"\r\n" );
document.write( "\"17%2AFD\"\"%22%22=%22%22\"\"+64\"\r\n" );
document.write( "\"FD\"\"%22%22=%22%22\"\"+64%2F17\"\r\n" );
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document.write( "ΔCFD ≅ ΔAEB is easy to show.\r\n" );
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document.write( "So FD = EB  by cpct\r\n" );
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document.write( "\"FD\"\"%22%22=%22%22\"\"EB\"\"%22%22=%22%22\"\"+64%2F17\"\r\n" );
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document.write( "BD = EB + EF + FD\r\n" );
document.write( "\"17\"\"%22%22=%22%22\"\"+64%2F17%2BEF%2B64%2F17\"\r\n" );
document.write( "\"17\"\"%22%22=%22%22\"\"+128%2F17%2BEF\"\r\n" );
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document.write( "Multiply though by 17\r\n" );
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document.write( "\"289\"\"%22%22=%22%22\"\"+128%2B17%2AEF\"\r\n" );
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document.write( "\"161\"\"%22%22=%22%22\"\"+17%2AEF\"\r\n" );
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document.write( "\"161%2F17\"\"%22%22=%22%22\"\"+EF\"\r\n" );
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document.write( "Edwin
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