document.write( "Question 98965: Determine the solutions for the following polynomial equation. \r
\n" ); document.write( "\n" ); document.write( "(2x+6)^2 =36
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Algebra.Com's Answer #72052 by doukungfoo(195)\"\" \"About 
You can put this solution on YOUR website!
This problem can be solved by using the quadratic formula
\n" ); document.write( "which is \"x=-b%2B-sqrt%28b%5E2-4ac%29%2F2a\"
\n" ); document.write( "but first it needs to be be simplified to the proper format \"ax%5E2%2Bbx%2Bc=0\"
\n" ); document.write( "\"%282x%2B6%29%5E2=36\"
\n" ); document.write( "first expand \"%282x%2B6%29%5E2\"
\n" ); document.write( "\"%282x%2B6%29%282x%2B6%29=36\"
\n" ); document.write( "Now multply \"%282x%2B6%29%282x%2B6%29\" using the FOIL method
\n" ); document.write( "so
\n" ); document.write( "\"%282x%2B6%29%282x%2B6%29=36\" becomes
\n" ); document.write( "\"4x%5E2%2B12x%2B12x%2B36=36\"
\n" ); document.write( "Now simplify by combining like terms
\n" ); document.write( "\"4x%5E2%2B24x%2B36=36\"
\n" ); document.write( "Next you want to set the equation equal to zero so that it will be in the proper format to use the quadratic formula
\n" ); document.write( "So subtract 36 from both sides of the equal sign
\n" ); document.write( "\"4x%5E2%2B24x%2B36-36=36-36\"
\n" ); document.write( "now we have
\n" ); document.write( "\"4x%5E2%2B24x%2B0=0\" compare it to this:
\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\" you can see that the a is represented by the number 4
\n" ); document.write( "the b is the number 24 and c is the number zero.
\n" ); document.write( "Now you are ready to use the quadratic formula to solve for x
\n" ); document.write( "\"x=-b%2B-sqrt%28b%5E2-4ac%29%2F2a\"
\n" ); document.write( "Just replace a,b, and c with the correct number. In this problem a=4, b=24, and c=0 so now the formula looks like this:
\n" ); document.write( "\"x=-24%2B-sqrt%2824%5E2-4%284%29%280%29%29%2F2%284%29\"
\n" ); document.write( "next just do the math, remembering to follow order of operations.
\n" ); document.write( "\"x=%28-24%2B-sqrt%28576%29%29%2F8\"
\n" ); document.write( "At this point you need to split the equation into two seperate equations. This is done because of the +- This is how we get two answers when solving for x.
\n" ); document.write( "So now we have:
\n" ); document.write( "\"x=%28-24%2Bsqrt%28576%29%29%2F8\" and \"x=%28-24-sqrt%28576%29%29%2F8\"
\n" ); document.write( "The squareroot of 576 is 24 so now we have this:
\n" ); document.write( "\"x=%28-24%2B24%29%2F8\" and \"x=%28-24-24%29%2F8\"
\n" ); document.write( "\"x=%280%29%2F8\" and \"x=%28-48%29%2F8\"
\n" ); document.write( "\"x=0\" and \"x=-6\"
\n" ); document.write( "So finally we get our answers and remember with a quadratic equation you should always get two answers. To check them just plug them back in to the original problem \"%282x%2B6%29%5E2=36\"
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