document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105654>Question 1105654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers are in the ratio of 5:8 their difference is 45. What is the smaller number?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720519 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the first number.<BR>\n" );
document.write( "y is the second number.\r<BR>\n" );
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document.write( "x/y = 5/8<BR>\n" );
document.write( "x = 5/8 * y\r<BR>\n" );
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document.write( "y - x = 45 (because y is bigger than x, the difference will be positive).\r<BR>\n" );
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document.write( "since x = 5/8 * y , then y - x = 45 becomes y - 5/8 * y = 45 which becomes (8-5)/8 * y = 45 which becomes 3/8 * y = 45\r<BR>\n" );
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document.write( "multiply both sides of this equation by 8/3 to get y = 45 * 8/3 which results in y = 15 * 8 which results in y = 120.\r<BR>\n" );
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document.write( "when y = 120, x = 5/8 * y becomes x = 5/8 * 120 which becomes x = 5 * 15 which results in x = 75.\r<BR>\n" );
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document.write( "you have x = 75 and y = 120.\r<BR>\n" );
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document.write( "x/y = 75/120 which becomes x/y =  15/24 which becomes x/y =  5/8.\r<BR>\n" );
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document.write( "you get x/y = 5/8 which can be written as x:y = 5:8 which is what you were given to start with.\r<BR>\n" );
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document.write( "y - x = 120 - 75 = 45 which is also what you were given to start with.\r<BR>\n" );
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document.write( "the solution is confirmed to be good.\r<BR>\n" );
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document.write( "y is the biggest number.<BR>\n" );
document.write( "x is the smallest number.\r<BR>\n" );
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document.write( "the solution is that the smallest number is 75.\r<BR>\n" );
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