document.write( "Question 1105615: Red balls=15, White balls=10, Blue balls=20, Yellow balls=5\r
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document.write( "If a ball was randomly selected; what is the probability of a ball
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document.write( "1) TO BE yellow OR red
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document.write( "2) NOT TO BE red OR blue
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document.write( "3) NOT TO BE white
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document.write( "4) TO BE yellow
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document.write( "5) TO BE red, white OR yellow\r
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document.write( "If two balls were selected with replacement; what is the probability of
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document.write( "1) both the balls to be white
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document.write( "2) first ball to be red and second ball to be white
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document.write( "3) none to be yellow
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document.write( "4) to be red OR white Or red AND white
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document.write( "5) second ball NOT to be a blue
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document.write( "6) first ball to be a yellow
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document.write( "7) at least one ball to be blue
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document.write( "8) for the most part one to be red
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document.write( "9) first to be white and second NOT to be white
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document.write( "10) only one to be red
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Algebra.Com's Answer #720474 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 50 balls \n" ); document.write( "1.20/50 or 2/5 \n" ); document.write( "2.White or yellow so 15/50 or 3/10 \n" ); document.write( "3.not to be white 40/50 or 4/5 \n" ); document.write( "4.to be yellow 5/50 or 1/10 \n" ); document.write( "5.To be red, white or yellow, 30/50 or 3/5 \n" ); document.write( "=== \n" ); document.write( "1.10/50*10/50 or 1/25 \n" ); document.write( "2.15/50*10/50 which is 3/50. \n" ); document.write( "3.0.9^0.81 \n" ); document.write( "4.Red or white is 1/2 ^2=1/4; red and white is 3/10*1/5 or 3/50. \n" ); document.write( "5.30/50 or 3/5 \n" ); document.write( "6.1/10 \n" ); document.write( "7.first2/5*second 2/5=4/25 for both and 2/5*3/5 plus 3/5*2/5=12/25 for 1, total is 16/25 for at least one ball to be blue. \n" ); document.write( "8.not clear. \n" ); document.write( "9.1/5*4/5=4/25 \n" ); document.write( "10.one red ball is 3/10. Only 1 is 3/10*7/10 + 7/10*3/10 or 42/100 or 0.42. \n" ); document.write( " |