document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105592>Question 1105592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coin is tossed 5 times; find the<BR>\n" );
document.write( "probability of getting at least 1 tail. Would you consider<BR>\n" );
document.write( "this event likely to happen? Explain your answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720462 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probability (P) (of getting at least one tail in 5 tosses) = 1 - P(0 tails in 5 tosses)<BR>\n" );
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document.write( "use binomial probability formula<BR>\n" );
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document.write( "P (k successes in n trials) = nCk * p^(k) * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!)<BR>\n" );
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document.write( "for this problem, p = 0.5, n = 5, k = 0<BR>\n" );
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document.write( "P (o tails in 5 tosses) = 5C0 * (0.5)^0 * (0.5)^(5-0) = 1 * 1 * (0.5)^5 = 0.03125<BR>\n" );
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document.write( "Probability (P) (of getting at least one tail in 5 tosses) = 1 - 0.03125 = 0.96875<BR>\n" );
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document.write( "yes, assuming we have a fair coin, we expect to have 5/2 tails when tossing 5 times which is > 1<BR>\n" );
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