document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105609>Question 1105609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center and the radius of the circle below . Show your work\r<BR>\n" );
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document.write( "X^2+6x+y^2-4y-68=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720459 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 +6x +y^2 -4y -68 = 0<BR>\n" );
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document.write( "add 68 to both sides of =<BR>\n" );
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document.write( "x^2 +6x +y^2 -4y = 68<BR>\n" );
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document.write( "complete the squares<BR>\n" );
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document.write( "x^2 +6x +9 + y^2 -4y +4 = 68 +13<BR>\n" );
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document.write( "factor the squares on both sides of =<BR>\n" );
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document.write( "(x+3)^2 +(y-2)^2 = 9^2<BR>\n" );
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document.write( "the equation is recognizable as a circle whose center is (-3,2) and radius of 9<BR>\n" );
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