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document.write( "He's no more help than the back of the book. LOL\r\n" );
document.write( "She didn't give the complex solutions.\r\n" );
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document.write( "Notice that if we interchange x and y, the system of equations\r\n" );
document.write( "simplifies to the same system, so if (x,y)=(p,q) is a solution,\r\n" );
document.write( "then so is (x,y)=(q,p) \r\n" );
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document.write( "Let y = kx\r\n" );
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document.write( "Solve each for x³\r\n" );
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document.write( "Equate the expressions for x³\r\n" );
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document.write( "Divide both sides by 8\r\n" );
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document.write( "Cross-multiply:\r\n" );
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document.write( "Factor 1-k² as the difference of squares:\r\n" );
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document.write( "Get 0 on the right\r\n" );
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document.write( "Factor out common factor (1+k)\r\n" );
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document.write( "Use the zero factor property:\r\n" );
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document.write( "1+k = 0; -3k²+10k-3 = 0\r\n" );
document.write( " k = -1; 3k²-10k+3 = 0\r\n" );
document.write( " (3k-1)(k-3) = 0 \r\n" );
document.write( " 3k-1 = 0; k-3 = 0\r\n" );
document.write( " 3k = 1; k = 3\r\n" );
document.write( " k = 1/3\r\n" );
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document.write( "We substitute those three values for k in:\r\n" );
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document.write( "Substituting k=-1\r\n" );
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document.write( "
, not possible:\r\n" );
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document.write( "Substituting k=1/3\r\n" );
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document.write( "Use zero-factor property:\r\n" );
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document.write( "x=3; x²+3x+9=0\r\n" );
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document.write( "And since y = kx = (1/3)x\r\n" );
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document.write( "when x = 3, y = (1/3)(1) = 1\r\n" );
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document.write( "So one solution is (x,y) = (3,1), and by swapping x and y, we\r\n" );
document.write( "have\r\n" );
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document.write( " (x,y) = (1,3)\r\n" );
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document.write( "and when
,
\r\n" );
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document.write( "So two more solutions are\r\n" );
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document.write( "and\r\n" );
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\r\n" );
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document.write( "And two more solutions by swapping x and y are\r\n" );
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\r\n" );
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document.write( "and\r\n" );
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document.write( "Edwin
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document.write( "