document.write( "Question 1105533: I have 27 coins that total $3.30. I have 3 times as many quarters as dimes; how many nickels do I have? This is my question and I have tried several ways to set the problem up but none give me the correct answer. How do I begin to set this up?\r
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document.write( "Thank You,
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document.write( "Iron Heart \n" );
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Algebra.Com's Answer #720401 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "With the information given in this way, I can't tell whether substitution or elimination would be easier. Since the other tutor showed a solution using substitution, let me try elimination. \n" ); document.write( "That means using two variables: \n" ); document.write( "let x = number of dimes \n" ); document.write( "then 3x = number of quarters \n" ); document.write( "let y = number of nickels \n" ); document.write( " \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(2) \n" ); document.write( "Subtracting (1) from (2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the number of dimes is x=3; the number of quarters is 3x=9; and since the total number of coins is 27, the number of nickels is 15. \n" ); document.write( "HMMM.... Looks very different than the solution using substitution... and both methods seem to require about the same a mount of work.... \n" ); document.write( " \n" ); document.write( " |