document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105530>Question 1105530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages two brothers is 38.four years ago the age of the elder brothers was the square of the younger brother's age.find their ages<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720399 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If the sum of their ages now is 38, then the sum of their ages 4 years ago was 30.<br><BR>\n" );
document.write( "Since 4 years ago the older brother's age was the square of the younger brother's age, you need to find two numbers, one the square of the other, whose sum is 30.  That should be easy;those two numbers are their ages 4 years ago.<br><BR>\n" );
document.write( "Then add 4 to each of their ages 4 years ago to get their current ages. </SPAN>\n" );
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