document.write( "Question 98979: My problem is written as; I had to name the property in each step. The first step they switched the x, so I think it's symmetric. step 2, the x came to be on the outsid and I'm thinking that's reflexive. I need help on these steps bcause they are confusing.\r
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document.write( "x(y+1)+(-1)x = x(y+1)+x(-1)
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document.write( " = x [(y+1)]+(-1)]
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document.write( " = x[y+(1+ (-1))]
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document.write( " = x [y+0]
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document.write( " = xy \n" );
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Algebra.Com's Answer #72039 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x(y+1)+(-1)x = x(y+1)+x(-1) \n" ); document.write( "commutative: (-1)x=x(-1) \n" ); document.write( "------------------ \n" ); document.write( "= x [(y+1)]+(-1)] \n" ); document.write( "distributive \n" ); document.write( "----------------- \n" ); document.write( "= x[y+(1+ (-1))] \n" ); document.write( "associative \n" ); document.write( "----------------- \n" ); document.write( "= x [y+0] \n" ); document.write( "additive inverse \n" ); document.write( "------------------- \n" ); document.write( "= xy \n" ); document.write( "additive identity \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |