document.write( "Question 1105530: the sum of the ages two brothers is 38.four years ago the age of the elder brothers was the square of the younger brother's age.find their ages
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Algebra.Com's Answer #720387 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"system%28x%2By=38%2Cy-4=%28x-4%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4%2B%28x-4%29%5E2=38\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%28x-4%29%5E2=34\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-8x%2B16%2Bx=34\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-7x=18\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-7x-18=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%28x-9%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "The value you need here is \"x=9\".\r
\n" ); document.write( "\n" ); document.write( "\"y=29\".
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