document.write( "Question 98975: A total of $18,000 is invested in two simple intrest accounts. On one of the accounts the annual simple intrest rate is 6.4%, and on the 2nd account the simple intrest rate is 5%. The amount of intrest earned for 1 year was $1103. How much is invested in each account. \n" ); document.write( "
Algebra.Com's Answer #72038 by checkley71(8403)\"\" \"About 
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.064x+.05(18000-x)=1103
\n" ); document.write( ".064x+900-.05x=1103
\n" ); document.write( ".014x=1103-900
\n" ); document.write( ".014x=203
\n" ); document.write( "x=203/.014
\n" ); document.write( "x=14500 amount of money invested @ 6.5%
\n" ); document.write( "18000-14500=3500 invested @ 5%.
\n" ); document.write( "proof
\n" ); document.write( "14500*.064+3500*.05=1103
\n" ); document.write( "928+175=1103
\n" ); document.write( "1103=1103
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