document.write( "Question 98975: A total of $18,000 is invested in two simple intrest accounts. On one of the accounts the annual simple intrest rate is 6.4%, and on the 2nd account the simple intrest rate is 5%. The amount of intrest earned for 1 year was $1103. How much is invested in each account. \n" ); document.write( "
Algebra.Com's Answer #72038 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .064x+.05(18000-x)=1103 \n" ); document.write( ".064x+900-.05x=1103 \n" ); document.write( ".014x=1103-900 \n" ); document.write( ".014x=203 \n" ); document.write( "x=203/.014 \n" ); document.write( "x=14500 amount of money invested @ 6.5% \n" ); document.write( "18000-14500=3500 invested @ 5%. \n" ); document.write( "proof \n" ); document.write( "14500*.064+3500*.05=1103 \n" ); document.write( "928+175=1103 \n" ); document.write( "1103=1103 \n" ); document.write( " \n" ); document.write( " |