document.write( "Question 1105533: I have 27 coins that total $3.30. I have 3 times as many quarters as dimes; how many nickels do I have? This is my question and I have tried several ways to set the problem up but none give me the correct answer. How do I begin to set this up?\r
\n" ); document.write( "\n" ); document.write( "Thank You,
\n" ); document.write( "Iron Heart
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Algebra.Com's Answer #720376 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
dimes=x
\n" ); document.write( "quarters=3x
\n" ); document.write( "nickels=27-4x, in other words, everything else
\n" ); document.write( ".10*x+.25(3x)+.05(27-4x)=3.30
\n" ); document.write( ".10x+.75x+1.35-0.20x=3.30
\n" ); document.write( "0.65x=1.95
\n" ); document.write( "x=3 dimes (0.30)
\n" ); document.write( "3x=9 quarters (2.25)
\n" ); document.write( "27-4x=15 nickels (0.75) ANSWER
\n" ); document.write( "adds to $3.30
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