document.write( "Question 1105498: Natasha invests $2100 in one account and $1400 in an account paying 2 % higher interest. At the end of one year she had earned $168 in interest. At what rates did she invest?\r
\n" ); document.write( "\n" ); document.write( "$2100 invested at %\r
\n" ); document.write( "\n" ); document.write( "$1400 invested at %
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Algebra.Com's Answer #720345 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "You can use some logical reasoning to simplify the required calculations a bit.

\n" ); document.write( "The \"extra\" 2% on the $1400 produces $28 in interest: \"1400%2A.02+=+28\". The remaining $140 of interest is from the whole $3500 invested at the lower rate.

\n" ); document.write( "\"3500x+=+140\"
\n" ); document.write( "\"x+=+140%2F3500+=+.04\"

\n" ); document.write( "The lower rate was .04 = 4%; so the higher rate was 6%.

\n" ); document.write( "$2100 was invested at 4%; $1400 was invested at 6$.
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