document.write( "Question 1105493: I need help with rearranging an equation. Can you please show a step by step method of how to get to the value of x. Thank you.\r
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document.write( "1600= 192/(0.12-x)-600 \n" );
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Algebra.Com's Answer #720320 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( "Think of the fraction 192/(0.12-x) as the variable z.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we'll say z = 192/(0.12-x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Allowing us to go from this \n" ); document.write( "1600 = 192/(0.12-x) - 600 \n" ); document.write( "to this \n" ); document.write( "1600 = z - 600\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At this point, you hopefully agree that this new equation is much easier to deal with. The sub-goal here is to solve for z. To do so, we undo the subtraction done to z by adding. We add 600 to both sides\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1600 = z - 600 \n" ); document.write( "1600+600 = z - 60+600 \n" ); document.write( "2200 = z \n" ); document.write( "z = 2200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We found the solution for z, but what we really want is the solution for x. So we need to get z back into terms of x. Replace z with the fraction written in blue above. So we'll replace z with 192/(0.12-x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We go from this \n" ); document.write( "z = 2200 \n" ); document.write( "to this \n" ); document.write( "192/(0.12-x) = 2200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Think of the 2200 on the right side as 2200/1. So we really have this equation \n" ); document.write( "192/(0.12-x) = 2200/1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we cross multiply \n" ); document.write( "192/(0.12-x) = 2200/1 \n" ); document.write( "192*1 = 2200(0.12-x) \n" ); document.write( "192 = 2200(0.12-x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next we distribute the 2200 through to each term inside the parenthesis \n" ); document.write( "192 = 2200(0.12-x) \n" ); document.write( "192 = 2200(0.12)+2200(-x) \n" ); document.write( "192 = 264-2200x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From here, we treat this as any other linear equation to solve \n" ); document.write( "192 = 264-2200x \n" ); document.write( "264-2200x = 192 \n" ); document.write( "-2200x+264 = 192 \n" ); document.write( "-2200x+264-264 = 192-264 ... subtract 264 from both sides \n" ); document.write( "-2200x = -72 \n" ); document.write( "-2200x/(-2200) = -72/(-2200) ... divide both sides by -2200 \n" ); document.write( "x = 72/2200 \n" ); document.write( "x = (8*9)/(8*275) \n" ); document.write( "x = 9/275 <<--- Exact Answer as a fraction \n" ); document.write( "x = 0.032727 <<--- Approximate Answer in decimal form(accurate to 6 decimal places; the '27' repeats forever)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The answer format (either exact or approximate) will depend on what your teacher wants. \n" ); document.write( " \n" ); document.write( " |