document.write( "Question 1105467: Five boxes are to be arranged on a shelf, but there is only enough space for three books. In how many ways can these books be arranged on the shelf?\r
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Algebra.Com's Answer #720316 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "I think you meant to write \"books\" instead of \"boxes\". \r
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\n" ); document.write( "\n" ); document.write( "We have five books but only enough space for three of them. \r
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\n" ); document.write( "\n" ); document.write( "Label the three empty spaces as
\n" ); document.write( "Slot A
\n" ); document.write( "Slot B
\n" ); document.write( "Slot C\r
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\n" ); document.write( "\n" ); document.write( "There are 5 choices for slot A.
\n" ); document.write( "After you've picked a book to go into slot A, there are 5-1 = 4 choices for slot B since you cannot have a book occupy more than one slot at a time.
\n" ); document.write( "For slot C, there are 3 choices left.\r
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\n" ); document.write( "\n" ); document.write( "So have 5*4*3 = 20*3 = 60 different permutations.\r
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\n" ); document.write( "\n" ); document.write( "If you wish to use a formula, then you can use the nPr formula
\n" ); document.write( "nPr = (n!)/(n-r)!
\n" ); document.write( "where you plug in n = 5 and r = 3 to get the same result of 60\r
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\n" ); document.write( "\n" ); document.write( "Answer: 60
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