document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98977>Question 98977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much square feet of surface area is in a cylinder 48' high and 80' diameter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72031 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the diameter is 80', the radius is 40' (which is half of the diameter)\r<BR>\n" );
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document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=FIND_the_Surface_area_and_Volume_of_a_cylinder.solver>Surface area and Volume of a cylinder</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>The surface area (SA) of a cylinder, excluding the base area and top area, is given by <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=SA+=+2%2Api%2AR%2AH ALIGN=MIDDLE  ALT=\"SA+=+2%2Api%2AR%2AH\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "   <BR>\n" );
document.write( "  When the areas of base and top are included, the surface area becomes <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=SA+=+2%2Api%2AR%2AH+%2B+2%2Api%2AR%5E2 ALIGN=MIDDLE  ALT=\"SA+=+2%2Api%2AR%2AH+%2B+2%2Api%2AR%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=SA+=+2%2Api%2AR%2A%28R%2BH%29 ALIGN=MIDDLE  ALT=\"SA+=+2%2Api%2AR%2A%28R%2BH%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  The volume of the cone can be found by the formula <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+pi%2AR%5E2%2AH ALIGN=MIDDLE  ALT=\"V+=+pi%2AR%5E2%2AH\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "  In our case the desired values are thus:<BR>\n" );
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document.write( "  SA (without base and top) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2A40%2A48+=+12063.715776 ALIGN=MIDDLE  ALT=\"2%2Api%2A40%2A48+=+12063.715776\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  SA (with base and top) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2A40%2A48+%2B+2%2Api%2A40%5E2+=+22116.812256 ALIGN=MIDDLE  ALT=\"2%2Api%2A40%2A48+%2B+2%2Api%2A40%5E2+=+22116.812256\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  V = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A40%5E2%2A48+=+241274.31552 ALIGN=MIDDLE  ALT=\"pi%2A40%5E2%2A48+=+241274.31552\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "  For more on this topic, refer to <A  rel=nofollow HREF=Surface_area.wikipedia>Surface area</A> and <A  rel=nofollow HREF=Volume.wikipedia>Volume</A>.<BR>\n" );
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