document.write( "Question 14365: The length of a rectangle 6 cm more than the width. If perimeter 48 cm,what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #7203 by bonster(299)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=6 cm more than the width \n" ); document.write( "then width =w and length=w+6\r \n" ); document.write( "\n" ); document.write( "p=2L+2W \n" ); document.write( "48=2(w+6)+2(w) \n" ); document.write( "48=2w+12+2w \n" ); document.write( "48=4w+12 \n" ); document.write( "36=4w \n" ); document.write( "w=9\r \n" ); document.write( "\n" ); document.write( "since width=w, the width is 9 cm \n" ); document.write( "since length =(w+6), the length is 15 cm. \n" ); document.write( " \n" ); document.write( " |