document.write( "Question 1105445: an adult and a young boy, standing on the ground are one metre apart .the height of the adult is 2 times the height of young boy. if at the mid-point of the line joining their feet the angular elevation of their tops are complementary , find the height of the young boy \n" ); document.write( "
Algebra.Com's Answer #720281 by KMST(5328)\"\" \"About 
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A very, very small adult!
\n" ); document.write( "
\n" ); document.write( "Let \"x\" be the height of the boy, in metres.
\n" ); document.write( "If the man and boy are standing on level ground,
\n" ); document.write( "their heights can be represented as vertical lines,
\n" ); document.write( "perpendicular to the horizontal ground.
\n" ); document.write( "The sketch below shows the two humans' heights,
\n" ); document.write( "the ground under them,
\n" ); document.write( "and the line segments connecting point M
\n" ); document.write( "(the mid-point of the line joining their feet)
\n" ); document.write( "to the top of their heights.
\n" ); document.write( " The red and green arcs show the angles of elevation from M to the top of the adult's and boy's heads.
\n" ); document.write( "Those two angles are complementary,
\n" ); document.write( "meaning that their measures add up to \"pi%2F2\" or \"90%5Eo\" .
\n" ); document.write( "As the two triangles are right triangles,
\n" ); document.write( "the acute angles in each triangle are also complementary,
\n" ); document.write( "meaning that their measures add up to \"pi%2F2\" or \"90%5Eo\" .
\n" ); document.write( "As a consequence, for each triangle, the angle not marked with an arc
\n" ); document.write( "is complementary to the marked angle in the other triangle.
\n" ); document.write( "That makes the triangles similar.
\n" ); document.write( "Similar triangles have proportional side lengths.
\n" ); document.write( "With side length measured in m,
\n" ); document.write( "\"2x%2F0.5=0.5%2Fx\"
\n" ); document.write( "\"2x%5E2=0.5%2A0.5\"
\n" ); document.write( "\"x%5E2=0.25%2F2\"
\n" ); document.write( "\"x%5E2=0.125\"
\n" ); document.write( "\"x=sqrt%280.125%29=approximately\"\"0.3536\"
\n" ); document.write( "That would make the height of the boy \"highlight%280.354m%29\" ,
\n" ); document.write( "and the height of the adult would be \"2%280.3536m%29=0.707m\" .
\n" ); document.write( "That would make that adult a very strong contender for the title of shortest man (or woman) alive.
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