document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105453>Question 1105453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman bought a number of items for $36. She realized that if she had bought 6 more items for the same money, she would have paid $3 less per item. How many items did she buy?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720279 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> bought x items at a price of $36/x per item.<BR>\n" );
document.write( "if she bought x=6 items for $36, the price would have been 36/(x+6)<BR>\n" );
document.write( "36/(x+6)+3=(36/x)<BR>\n" );
document.write( "multiply everything by x(x+6) to clear fractions<BR>\n" );
document.write( "36x+3x^2+18x=36x+216<BR>\n" );
document.write( "3x^2+18x-216=0<BR>\n" );
document.write( "x^2+6x-72=0<BR>\n" );
document.write( "(x+12)(x-6)=0<BR>\n" );
document.write( "x=6 items, only positive root. ANSWER<BR>\n" );
document.write( "They were $6 each, but had she bought 6 more items for 36, they would have been $36/12=$3 each. </SPAN>\n" );
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