document.write( "Question 1105424: Let X be the variable that represents the height of the individuals of a given population. Suppose that X has approximately normal distribution, with mean 170 cm and variance of 100 cm ^ 2.
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document.write( "a) What is the probability that an individual of this population has height less than 175 cm?
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document.write( "b) Find the points a and b, symmetric to the mean, such that P (a< x < b) = 0,50 \n" );
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Algebra.Com's Answer #720240 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Less than 175 is z<(175-170)/10, (x-mean)/sd, and sd is the sqrt (var) \n" ); document.write( "z<+(5/10) or +(1/2) \n" ); document.write( "Probability is 0.6915. \n" ); document.write( "The probability of being symmetric to the mean and having a probability of 0.50 requires the z-value of 0.2500 probability, which is +/-0.675 \n" ); document.write( "z=0.675=(x-170)/10 \n" ); document.write( "6.75=x-170 \n" ); document.write( "x=176.75 \n" ); document.write( "(163.25, 176.75) \n" ); document.write( " |