document.write( "Question 1105385: certain class contains 60% of boys and 40% of girls, all aged between 17 and 27 years. It is known that 80% of young people of both sexes are under 21 years of age and that among girls, 10% are over 21 years.\r
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document.write( "a) a person is chosen and it is verified that he is under 21 years. What is the probability of being a girl?
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document.write( "b) a person is chosen at random. What is the probability of being a boy under the age of 21?
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document.write( "c) choose a boy at random. How likely is he to be less than 21 years old? \n" );
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Algebra.Com's Answer #720225 by natolino_2017(77)![]() ![]() ![]() You can put this solution on YOUR website! Let be the events A: The picked person is a Girl. \n" ); document.write( " B: the picked person is under 21 or 21.\r \n" ); document.write( "\n" ); document.write( "First P(A) = 40%. P(B) = 80%.\r \n" ); document.write( "\n" ); document.write( "a) P(A/B) = P(A&B)/P(B)=(90%(40%))/(80%)=9/20. \n" ); document.write( "b) P(A^c&B) = 60%(80%) = 12/25. \n" ); document.write( "c) P(B/A^c) = P(B&A^c)/P(A^c) = (12/25)/60% =4/5.\r \n" ); document.write( "\n" ); document.write( "#natolino_ \n" ); document.write( " \n" ); document.write( " |