document.write( "Question 1104569: A Pillar is dug into the ground 1 third of its length.
\n" ); document.write( "half of the length is in water.
\n" ); document.write( "2 meters peak out of the water.
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Algebra.Com's Answer #720223 by Theo(13342)\"\" \"About 
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A Pillar is dug into the ground 1 third of its length.\r
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\n" ); document.write( "\n" ); document.write( "this means 1/3 of the length of the pillar is in the ground while 2/3 is above the ground.\r
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\n" ); document.write( "\n" ); document.write( "half of the length is in water.\r
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\n" ); document.write( "\n" ); document.write( "you've got 1/3 of the length in the ground and 1/2 of the length in the water.\r
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\n" ); document.write( "\n" ); document.write( "the total length of the pillar that is either in the ground or in the water is 1/3 + 1/2 = 2/6 + 3/6 = 5/6.\r
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\n" ); document.write( "\n" ); document.write( "that means that 1/6 of the pillar is neither in the ground or in the water.\r
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\n" ); document.write( "\n" ); document.write( "let x equal the length of the pillar.\r
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\n" ); document.write( "\n" ); document.write( "since 2 meters is neither in the ground nor in the water, then 2 meters represents 1/6 of the length of the pillar.\r
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\n" ); document.write( "\n" ); document.write( "1/6 * x = 2
\n" ); document.write( "multiply both sides of this equation by 6 to get x = 12 meters in length total.\r
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\n" ); document.write( "\n" ); document.write( "1/3 of 12, or 4 meters, is in the ground.
\n" ); document.write( "1/2 of 12, or 6 meters, is in the water.
\n" ); document.write( "1/6 of 12, or 2 meters, is not in the ground or in the water.\r
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