document.write( "Question 98949: find two numbers with a sum of 15 and a differnce of 4. \n" ); document.write( "
Algebra.Com's Answer #72019 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
x+y=15
\n" ); document.write( "x-y=4
\n" ); document.write( ".
\n" ); document.write( "Solving using the substitute method:
\n" ); document.write( "x+y=15
\n" ); document.write( "x=-y+15
\n" ); document.write( ".
\n" ); document.write( "Substitute (x=-y+15) back into the second equation and solve for the y-term
\n" ); document.write( "x-y=4
\n" ); document.write( "(-y+15)-y=4
\n" ); document.write( "-2y+15=4
\n" ); document.write( "-2y=-15+4
\n" ); document.write( "-2y=-11
\n" ); document.write( "y=11/2
\n" ); document.write( ".
\n" ); document.write( "Solve for the x-term by substituting (y=11/2) back into either equation and solve for the x-term:
\n" ); document.write( "x-y=4
\n" ); document.write( "x-(11/2)=4
\n" ); document.write( "x=4+11/2
\n" ); document.write( "x=19/2
\n" ); document.write( ".
\n" ); document.write( "Checking:
\n" ); document.write( "x-y=4
\n" ); document.write( "(19/2)-(11/2)=4
\n" ); document.write( "8/2=4
\n" ); document.write( "4=4 [checks out]
\n" ); document.write( "
\n" ); document.write( "
\n" );