document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105365>Question 1105365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help with this question: Two consecutive whole numbers (x and x+1) when the product of these numbers are subtracted from 47 times the first number (x), the answer is 360. what is x?<BR>\n" );
document.write( "i have tried using the quadratic equation. I cannot get the answer to a whole number. my equation used to insert in the quadratic was: x(x+1)-47x-360=0.<BR>\n" );
document.write( "can you please help and include all your workings so i can learn for next time. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720169 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 47x - x*(x+1) = 360<BR>\n" );
document.write( "47x - x^2 - x - 360 = 0<BR>\n" );
document.write( "x^2 - 46x + 360 = 0<BR>\n" );
document.write( "(x-10)*(x-36) = 0<BR>\n" );
document.write( "x = 10, 36<BR>\n" );
document.write( " </SPAN>\n" );
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