document.write( "Question 1105324: The ice cream cones at the convenience store are about 5 inches tall and 2 inches wide. A new \"lite\" cone will be the same height but only 50% of the volume. How wide will the \"lite\" be? \n" ); document.write( "

Algebra.Com's Answer #720130 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "The volume of a cone is $\"V+=+%281%2F3%29%28pi%29%28r%5E2%29%28h%29\"$ where r is the radius (half the \"width\") and h is the height.

\n" ); document.write( "If the lite cone cuts the volume of the cone by a factor of 2 and the height stays the same, then \"r^2\" in the formula gets cut by a factor of 2, which means \"r\" is cut by a factor of the square root of 2.

\n" ); document.write( "If the radius is cut by a factor of the square root of 2, then so too is the width of the cone.

\n" ); document.write( "So the width of the lite cone is the \"original\" width, divided by the square root of 2: $\"2%2Fsqrt%282%29+=+sqrt%282%29\"$ . \n" ); document.write( "

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