document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98935>Question 98935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system by the substitution method. Indicate wether each system is independent, inconsistent, or dependent.\r<BR>\n" );
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document.write( "x-y=3<BR>\n" );
document.write( "3x-2y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72009 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-y=3 [re-write]<BR>\n" );
document.write( "-y=-x+3<BR>\n" );
document.write( "y=x-3<BR>\n" );
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document.write( "substitute into the second equation:<BR>\n" );
document.write( "3x-2y=3<BR>\n" );
document.write( "3x-2(x-3)=3<BR>\n" );
document.write( "3x-2x+6=3<BR>\n" );
document.write( "x+6=3<BR>\n" );
document.write( "x=3-6<BR>\n" );
document.write( "x=-3<BR>\n" );
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document.write( "Substitute (x=-3) back into either of the original equatino and solve for the y-term:<BR>\n" );
document.write( "3x-2y=3<BR>\n" );
document.write( "3(-3)-2y=3<BR>\n" );
document.write( "-9-2y=3<BR>\n" );
document.write( "-2y=3+9<BR>\n" );
document.write( "-2y=12<BR>\n" );
document.write( "y=-6<BR>\n" );
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document.write( "Check by plugging (x=-3) and (y=-6) back into either equation and solve.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );