document.write( "Question 1105298: Yuan invested $1200, part at 4.5% per annum and the remainder at 6.5% per annum. After one year, Yuan had $70.60 in interest. Determine how much money she invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #720083 by ikleyn(52818)\"\" \"About 
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document.write( "interest + interest       = total interest\r\n" );
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document.write( "0.045*x  + 0.065*(1200-x) = 70.60\r\n" );
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document.write( "0.045x + 0.065*1200 - 0.065x = 70.60\r\n" );
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document.write( "-0.02x = 70.60 - 0.065*1200 = -7.4  ====>  x = \"%28-7.4%29%2F%28-0.02%29\" = 370.\r\n" );
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document.write( "Answer.  $370 invested at 4.5%; the rest 1200-370 = 830 dollars invested at 6.5%.\r\n" );
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\n" ); document.write( "It is very standard problem on investments.\r
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\n" ); document.write( "\n" ); document.write( "To see other solved problems of this kind (and other approaches and other solution methods used), look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Using systems of equations to solve problems on investment\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic \"Systems of two linear equations in two unknowns\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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