document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105260>Question 1105260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations using matrices. Use Gaussian elimination with back-substitution.  x + y + z      =      -5 <BR>\n" );
document.write( "x - y + 3z     =     -1  <BR>\n" );
document.write( "4x + y + z    =     -2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720056 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> back substitution would be to take the solution in row three and apply it to row two\r<BR>\n" );
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document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=matrix%283%2C4%2C1%2C0%2C2%2C-3%2C0%2C1%2C-1%2C-2%2C0%2C0%2C1%2C-2%29 ALIGN=MIDDLE  ALT=\"matrix%283%2C4%2C1%2C0%2C2%2C-3%2C0%2C1%2C-1%2C-2%2C0%2C0%2C1%2C-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "then  take the solution in row two and apply it to row one </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );