document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105264>Question 1105264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.\r<BR>\n" );
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document.write( "Can someone help me with this? I have to do it step by step and I'm not sure how to. I will particate if you guide me. \r<BR>\n" );
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document.write( "Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720047 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> by inspecting Pascal's triangle, the following formula is apparent <BR>\n" );
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document.write( "(a+b)^n = a^n + (nC1)a^(n-1)b + (nC2)a^(n-1)q^2 +...+(nCn-1)ab^(n-1) + b^n<BR>\n" );
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document.write( "our n = 5 and p=0.3<BR>\n" );
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document.write( "for a binomial distribution q = 1-p, for this problem q = 0.7 and a = p and b = q<BR>\n" );
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document.write( "nCr = n! / (r! * (n-1)!)<BR>\n" );
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document.write( "you are asked to calculate each term for (0.3 + 0.7)^5<BR>\n" );
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document.write( "Note that each term is a probability of k failures in n trials<BR>\n" );
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document.write( "Probability (P) ( 0 failures in 5 trials ) = (.3)^5<BR>\n" );
document.write( "Probability (P) ( 1 failure  in 5 trials) = 5C1 * (.3)^4 * (.7)<BR>\n" );
document.write( "Probability (P) ( 2 failures in 5 trials) = 5C2 * (.3)^3 * (.7)^2<BR>\n" );
document.write( "Probability (P) ( 3 failures in 5 trials) = 5C3 * (.3)^2 * (.7)^3<BR>\n" );
document.write( "Probability (P) ( 4 failures in 5 trials) = 5C3 * (.3) * (.7)^4<BR>\n" );
document.write( "Probability (P) ( 5 failures in 5 trials) = (.7)^5<BR>\n" );
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