document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105177>Question 1105177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If (2rs)^-1 = 3s^-2, what is the value of r/s ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719963 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is 1/(2rs)=3/s^2<BR>\n" );
document.write( "Therefore, s^2/2rs=3<BR>\n" );
document.write( "s/2r=3<BR>\n" );
document.write( "s/r=6<BR>\n" );
document.write( "Check using s=12 and r=2<BR>\n" );
document.write( "(48)^-1=3/144, and both are 1/48. </SPAN>\n" );
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