document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1105186>Question 1105186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A species of bacteria doubles every 2 hours, so that a culture of 200 bacteria would grow to 400 after 2 hours and 800 after 4 hours. If there were b bacteria initially, which of the following expressions correctly describes the amount of bacteria present after one day? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719933 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=Pe^kt<BR>\n" );
document.write( "A/P=2=e^kt<BR>\n" );
document.write( "ln2=kt, and t=2 hours<BR>\n" );
document.write( "ln2=2k<BR>\n" );
document.write( "k=(1/2)ln 2.<BR>\n" );
document.write( "After one day, which is 24 hours,<BR>\n" );
document.write( "A=b*e^(12*ln 2)<BR>\n" );
document.write( "A=4096*b </SPAN>\n" );
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