document.write( "Question 1105147: n airplane flies 355 miles to city A. Then, with better winds, it continues on to city B, 448 miles from A, at a speed 14.0 mi./h greater than on the first leg of the trip. The total flying time was 5.20 h. Find the speed at which the plane travelled to city A. \n" ); document.write( "
Algebra.Com's Answer #719885 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
Better winds must mean, \"increased wind speed in the traveling direction\".
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document.write( "            SPEED       TIME              DISTANCE\r\n" );
document.write( "To A           r        355/r               355\r\n" );
document.write( "To B         r+14       448/(r+14)          448\r\n" );
document.write( "Total                   5.2\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28355%2Fr%2B448%2F%28r%2B14%29=5.2%29\"
\n" ); document.write( "Solve this for r.\r
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\n" ); document.write( "\n" ); document.write( "Simplification using the algebra steps should lead to something equivalent to \"5.2r%5E2-730.2r-4970=0\"\r
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\n" ); document.write( "\n" ); document.write( "Discriminant is \"636568.04\" and \"sqrt%28636568.04%29=797.85214\";
\n" ); document.write( "continuing on to using general quadratic formula solution,
\n" ); document.write( "\"r=%28730.2%2B797.85214%29%2F10.4\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28r=146.9%29\"
\n" ); document.write( "and when checked in the original equation might be about 5.19 or 5.2, so this solution works.
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