document.write( "Question 1105147: n airplane flies 355 miles to city A. Then, with better winds, it continues on to city B, 448 miles from A, at a speed 14.0 mi./h greater than on the first leg of the trip. The total flying time was 5.20 h. Find the speed at which the plane travelled to city A. \n" ); document.write( "
Algebra.Com's Answer #719885 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! Better winds must mean, \"increased wind speed in the traveling direction\". \n" ); document.write( " \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "To A r 355/r 355\r\n" ); document.write( "To B r+14 448/(r+14) 448\r\n" ); document.write( "Total 5.2\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve this for r.\r \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( "\n" ); document.write( "Simplification using the algebra steps should lead to something equivalent to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Discriminant is \n" ); document.write( "continuing on to using general quadratic formula solution, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "and when checked in the original equation might be about 5.19 or 5.2, so this solution works. \n" ); document.write( " |