document.write( "Question 1105103: Pythagorean Theorem:
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document.write( "side A^2+Side B^2=hypotenuse C^2\r
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document.write( "(x-2)^2+(x-4)^2=x^2\r
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document.write( "work:
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document.write( "2x^2-36=x^2
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document.write( "2x^2=x^2+36
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document.write( "x^2=36
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document.write( "Square root both sides
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document.write( "x=6\r
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document.write( "Incorrect though. Not sure what I did wrong. \n" );
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Algebra.Com's Answer #719836 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! (x-2)^2 +(x-4)^2 = x^2 \n" ); document.write( ": \n" ); document.write( "x^2 -4x +4 +x^2 -8x + 16 = x^2 \n" ); document.write( ": \n" ); document.write( "2x^2 -12x +20 = x^2 \n" ); document.write( ": \n" ); document.write( "x^2 -12x +20 = 0 \n" ); document.write( ": \n" ); document.write( "(x-10) * (x-2) = 0 \n" ); document.write( ": \n" ); document.write( "x-10 = 0 \n" ); document.write( "x = 10 \n" ); document.write( ": \n" ); document.write( "x-2 = 0 \n" ); document.write( "x = 2 \n" ); document.write( ": \n" ); document.write( "******************************************************* \n" ); document.write( "x = 10 or x = 2, so we have two possible right triangles \n" ); document.write( "8, 6, 10 or 0, -2, 2 \n" ); document.write( "we reject the 0, -2, 2 triangle and select 8, 6, 10 triangle \n" ); document.write( ": \n" ); document.write( "check answers by substituting for x in original equation \n" ); document.write( ": \n" ); document.write( "x = 10 \n" ); document.write( "(10-2)^2 + (10-4)^2 = 10^2 \n" ); document.write( "64 + 36 = 100 \n" ); document.write( "100 = 100 \n" ); document.write( ": \n" ); document.write( "x = 2 \n" ); document.write( "(2-2)^2 + (2-4)^2 = 2^2 \n" ); document.write( "4 = 4 \n" ); document.write( ": \n" ); document.write( "our answers check \n" ); document.write( "******************************************** \n" ); document.write( ": \n" ); document.write( " |