document.write( "Question 1105103: Pythagorean Theorem:
\n" ); document.write( "side A^2+Side B^2=hypotenuse C^2\r
\n" ); document.write( "\n" ); document.write( "(x-2)^2+(x-4)^2=x^2\r
\n" ); document.write( "\n" ); document.write( "work:
\n" ); document.write( "2x^2-36=x^2
\n" ); document.write( "2x^2=x^2+36
\n" ); document.write( "x^2=36
\n" ); document.write( "Square root both sides
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "Incorrect though. Not sure what I did wrong.
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Algebra.Com's Answer #719836 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
(x-2)^2 +(x-4)^2 = x^2
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\n" ); document.write( "x^2 -4x +4 +x^2 -8x + 16 = x^2
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\n" ); document.write( "2x^2 -12x +20 = x^2
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\n" ); document.write( "x^2 -12x +20 = 0
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\n" ); document.write( "(x-10) * (x-2) = 0
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\n" ); document.write( "x-10 = 0
\n" ); document.write( "x = 10
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\n" ); document.write( "x-2 = 0
\n" ); document.write( "x = 2
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\n" ); document.write( "x = 10 or x = 2, so we have two possible right triangles
\n" ); document.write( "8, 6, 10 or 0, -2, 2
\n" ); document.write( "we reject the 0, -2, 2 triangle and select 8, 6, 10 triangle
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\n" ); document.write( "check answers by substituting for x in original equation
\n" ); document.write( ":
\n" ); document.write( "x = 10
\n" ); document.write( "(10-2)^2 + (10-4)^2 = 10^2
\n" ); document.write( "64 + 36 = 100
\n" ); document.write( "100 = 100
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\n" ); document.write( "x = 2
\n" ); document.write( "(2-2)^2 + (2-4)^2 = 2^2
\n" ); document.write( "4 = 4
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\n" ); document.write( "our answers check
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