document.write( "Question 1105089: if a cyclist had gone 3km per hour faster, he would have have taken 1 hour and 20 minutes less to ride 80kms. What time did he take
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Algebra.Com's Answer #719822 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "                SPEED      TIME        DISTANCE\r\n" );
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document.write( "DONE              r         80/r          80\r\n" );
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document.write( "IF               r+3       80/(r+3)       80\r\n" );
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document.write( "DIFFERENCE                 \r\n" );
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\n" ); document.write( "\n" ); document.write( "He took $\"80%2Fr\"$ hours for the trip.\r
\n" ); document.write( "\n" ); document.write( " $\"highlight_green%2880%2Fr-80%2F%28r%2B3%29=1%261%2F3%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"80%2Fr-80%2F%28r%2B3%29=4%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"20%2Fr-20%2F%28r%2B3%29=1%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"60%2Fr-60%2F%28r%2B3%29=1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"60%28r%2B3%29-60r=r%5E2%2B3r\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"60r%2B180-60r=r%5E2%2B3r\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"180=r%5E2%2B3r\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"r%5E2%2B3r-180=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28r-12%29%28r%2B15%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( " $\"highlight_green%28r=12%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Time taken was $\"80%2F12=40%2F6=20%2F3=highlight%286%262%2F3%29\"$ , hours.
\n" ); document.write( "6 hours 40 minutes \n" ); document.write( "

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